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sched/core: Make sched_ttwu_pending() atomic in time

Since all tasks on the wake_list are woken under a single rq->lock
avoid calling update_rq_clock() for each task.

Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Signed-off-by: Ingo Molnar <mingo@kernel.org>
Peter Zijlstra 8 năm trước cách đây
mục cha
commit
77558e4d01
1 tập tin đã thay đổi với 3 bổ sung1 xóa
  1. 3 1
      kernel/sched/core.c

+ 3 - 1
kernel/sched/core.c

@@ -1685,7 +1685,7 @@ static void
 ttwu_do_activate(struct rq *rq, struct task_struct *p, int wake_flags,
 		 struct rq_flags *rf)
 {
-	int en_flags = ENQUEUE_WAKEUP;
+	int en_flags = ENQUEUE_WAKEUP | ENQUEUE_NOCLOCK;
 
 	lockdep_assert_held(&rq->lock);
 
@@ -1737,6 +1737,7 @@ void sched_ttwu_pending(void)
 		return;
 
 	rq_lock_irqsave(rq, &rf);
+	update_rq_clock(rq);
 
 	while (llist) {
 		int wake_flags = 0;
@@ -1849,6 +1850,7 @@ static void ttwu_queue(struct task_struct *p, int cpu, int wake_flags)
 #endif
 
 	rq_lock(rq, &rf);
+	update_rq_clock(rq);
 	ttwu_do_activate(rq, p, wake_flags, &rf);
 	rq_unlock(rq, &rf);
 }