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regulator: core: don't require a supply when supply_name is specified

Regulator drivers may specify regulator_desc->supply_name which
regulator_register() will use to find the supply node for a regulator.
If no supply was specified in the device tree or the supply has yet
to be registered regulator_register() will fail, deferring the probe
of the regulator.  In the case where no supply node was specified in the
device tree, there is no supply and it is pointless to try and find one
later, so go ahead and add the regulator without the supply.

Signed-off-by: Andrew Bresticker <abrestic@chromium.org>
Signed-off-by: Mark Brown <broonie@opensource.wolfsonmicro.com>
Andrew Bresticker 12 년 전
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1개의 변경된 파일9개의 추가작업 그리고 1개의 파일을 삭제
  1. 9 1
      drivers/regulator/core.c

+ 9 - 1
drivers/regulator/core.c

@@ -3477,7 +3477,14 @@ regulator_register(const struct regulator_desc *regulator_desc,
 
 		r = regulator_dev_lookup(dev, supply, &ret);
 
-		if (!r) {
+		if (ret == -ENODEV) {
+			/*
+			 * No supply was specified for this regulator and
+			 * there will never be one.
+			 */
+			ret = 0;
+			goto add_dev;
+		} else if (!r) {
 			dev_err(dev, "Failed to find supply %s\n", supply);
 			ret = -EPROBE_DEFER;
 			goto scrub;
@@ -3495,6 +3502,7 @@ regulator_register(const struct regulator_desc *regulator_desc,
 		}
 	}
 
+add_dev:
 	/* add consumers devices */
 	if (init_data) {
 		for (i = 0; i < init_data->num_consumer_supplies; i++) {