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drm/amdgpu: avoid the modulo in amdgpu_vm_get_entry

We can do this with a simple mask as well.

Signed-off-by: Christian König <christian.koenig@amd.com>
Reviewed-by: Chunming Zhou <david1.zhou@amd.com>
Signed-off-by: Alex Deucher <alexander.deucher@amd.com>
Christian König 7 năm trước cách đây
mục cha
commit
e3a1b32a12
1 tập tin đã thay đổi với 3 bổ sung3 xóa
  1. 3 3
      drivers/gpu/drm/amd/amdgpu/amdgpu_vm.c

+ 3 - 3
drivers/gpu/drm/amd/amdgpu/amdgpu_vm.c

@@ -1285,11 +1285,11 @@ void amdgpu_vm_get_entry(struct amdgpu_pte_update_params *p, uint64_t addr,
 	*parent = NULL;
 	*entry = &p->vm->root;
 	while ((*entry)->entries) {
-		unsigned idx = addr >> amdgpu_vm_level_shift(p->adev, level++);
+		unsigned shift = amdgpu_vm_level_shift(p->adev, level++);
 
-		idx %= amdgpu_bo_size((*entry)->base.bo) / 8;
 		*parent = *entry;
-		*entry = &(*entry)->entries[idx];
+		*entry = &(*entry)->entries[addr >> shift];
+		addr &= (1ULL << shift) - 1;
 	}
 
 	if (level != p->adev->vm_manager.num_level)