pinctrl: simplify check for pin request conflicts

This is a non-functional change, which deletes code duplication in two
of four if-if branches by reordering the checks. Functional identity
of the code change can be shown by running through the whole truth table
of boolean arguments.

Signed-off-by: Vladimir Zapolskiy <vz@mleia.com>
Signed-off-by: Linus Walleij <linus.walleij@linaro.org>

drivers/pinctrl/pinmux.c

@@ -99,37 +99,24 @@ static int pin_request(struct pinctrl_dev *pctldev,
 	dev_dbg(pctldev->dev, "request pin %d (%s) for %s\n",
 		pin, desc->name, owner);
 
-	if (gpio_range) {
-		/* There's no need to support multiple GPIO requests */
-		if (desc->gpio_owner) {
-			dev_err(pctldev->dev,
-				"pin %s already requested by %s; cannot claim for %s\n",
-				desc->name, desc->gpio_owner, owner);
-			goto out;
-		}
-		if (ops->strict && desc->mux_usecount &&
-		    strcmp(desc->mux_owner, owner)) {
-			dev_err(pctldev->dev,
-				"pin %s already requested by %s; cannot claim for %s\n",
-				desc->name, desc->mux_owner, owner);
-			goto out;
-		}
+	if ((!gpio_range || ops->strict) &&
+	    desc->mux_usecount && strcmp(desc->mux_owner, owner)) {
+		dev_err(pctldev->dev,
+			"pin %s already requested by %s; cannot claim for %s\n",
+			desc->name, desc->mux_owner, owner);
+		goto out;
+	}
+
+	if ((gpio_range || ops->strict) && desc->gpio_owner) {
+		dev_err(pctldev->dev,
+			"pin %s already requested by %s; cannot claim for %s\n",
+			desc->name, desc->gpio_owner, owner);
+		goto out;
+	}
 
+	if (gpio_range) {
 		desc->gpio_owner = owner;
 	} else {
-		if (desc->mux_usecount && strcmp(desc->mux_owner, owner)) {
-			dev_err(pctldev->dev,
-				"pin %s already requested by %s; cannot claim for %s\n",
-				desc->name, desc->mux_owner, owner);
-			goto out;
-		}
-		if (ops->strict && desc->gpio_owner) {
-			dev_err(pctldev->dev,
-				"pin %s already requested by %s; cannot claim for %s\n",
-				desc->name, desc->gpio_owner, owner);
-			goto out;
-		}
-
 		desc->mux_usecount++;
 		if (desc->mux_usecount > 1)
 			return 0;