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sched/core: Remove TASK_ALL

It's unused:

  $ git grep "\<TASK_ALL\>" | wc -l
  1

... and it is also dangerous, kill the bugger.

Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Signed-off-by: Sebastian Andrzej Siewior <bigeasy@linutronix.de>
Acked-by: Thomas Gleixner <tglx@linutronix.de>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Link: http://lkml.kernel.org/r/20180227160510.10829-1-bigeasy@linutronix.de
Signed-off-by: Ingo Molnar <mingo@kernel.org>
Peter Zijlstra 7 năm trước cách đây
mục cha
commit
9e49e2447c
1 tập tin đã thay đổi với 0 bổ sung1 xóa
  1. 0 1
      include/linux/sched.h

+ 0 - 1
include/linux/sched.h

@@ -93,7 +93,6 @@ struct task_group;
 
 /* Convenience macros for the sake of wake_up(): */
 #define TASK_NORMAL			(TASK_INTERRUPTIBLE | TASK_UNINTERRUPTIBLE)
-#define TASK_ALL			(TASK_NORMAL | __TASK_STOPPED | __TASK_TRACED)
 
 /* get_task_state(): */
 #define TASK_REPORT			(TASK_RUNNING | TASK_INTERRUPTIBLE | \