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lib: bitmap: eliminate branch in __bitmap_shift_right

We can shift the bits from lower and upper into place before assembling
dst[k]; moving the shift of upper into the branch where we already know
that rem is non-zero allows us to remove a conditional.

Signed-off-by: Rasmus Villemoes <linux@rasmusvillemoes.dk>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
Rasmus Villemoes 10 年之前
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共有 1 个文件被更改,包括 3 次插入3 次删除
  1. 3 3
      lib/bitmap.c

+ 3 - 3
lib/bitmap.c

@@ -129,13 +129,13 @@ void __bitmap_shift_right(unsigned long *dst, const unsigned long *src,
 			upper = src[off + k + 1];
 			if (off + k + 1 == lim - 1 && left)
 				upper &= mask;
+			upper <<= (BITS_PER_LONG - rem);
 		}
 		lower = src[off + k];
 		if (left && off + k == lim - 1)
 			lower &= mask;
-		dst[k] = lower >> rem;
-		if (rem)
-			dst[k] |= upper << (BITS_PER_LONG - rem);
+		lower >>= rem;
+		dst[k] = lower | upper;
 		if (left && k == lim - 1)
 			dst[k] &= mask;
 	}