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drm/i2c/tda998x: Fix signed overflow issue

This is C standard hair-splitting, but afaict
- sum will be promoted to signed int in computation since
  uint8_t fits
- signed overflow is undefined.

No we need to add up an awful lot of bytes to actually make it
overflow. But I guess the real risk is gcc spotting this and going
bananas. Fix this by simply using unsigned in to force all computations
to use the well-defined unsigned behaviour.

Spotted by coverity.

v2: Simplify the entire computation as suggested by Jean.

Cc: Russell King <rmk+kernel@arm.linux.org.uk>
Cc: Rob Clark <robdclark@gmail.com>
Cc: Jean-Francois Moine <moinejf@free.fr>
Reviewed-by: David Herrmann <dh.herrmann@gmail.com>
Signed-off-by: Daniel Vetter <daniel.vetter@ffwll.ch>
Daniel Vetter 11 лет назад
Родитель
Сommit
8268bd48af
1 измененных файлов с 3 добавлено и 3 удалено
  1. 3 3
      drivers/gpu/drm/i2c/tda998x_drv.c

+ 3 - 3
drivers/gpu/drm/i2c/tda998x_drv.c

@@ -568,11 +568,11 @@ static irqreturn_t tda998x_irq_thread(int irq, void *data)
 
 static uint8_t tda998x_cksum(uint8_t *buf, size_t bytes)
 {
-	uint8_t sum = 0;
+	int sum = 0;
 
 	while (bytes--)
-		sum += *buf++;
-	return (255 - sum) + 1;
+		sum -= *buf++;
+	return sum;
 }
 
 #define HB(x) (x)