crypto: md4 - Use ARRAY_SIZE

ARRAY_SIZE is more concise to use when the size of an array is divided by
the size of its type or the size of its first element.

The semantic patch that makes this change is as follows:
(http://www.emn.fr/x-info/coccinelle/)

// <smpl>
@i@
@@

#include <linux/kernel.h>

@depends on i using "paren.iso"@
type T;
T[] E;
@@

- (sizeof(E)/sizeof(T))
+ ARRAY_SIZE(E)
// </smpl>

Signed-off-by: Julia Lawall <julia@diku.dk>
Signed-off-by: Herbert Xu <herbert@gondor.apana.org.au>

crypto/md4.c

@@ -148,7 +148,7 @@ static void md4_transform(u32 *hash, u32 const *in)
 
 static inline void md4_transform_helper(struct md4_ctx *ctx)
 {
-	le32_to_cpu_array(ctx->block, sizeof(ctx->block) / sizeof(u32));
+	le32_to_cpu_array(ctx->block, ARRAY_SIZE(ctx->block));
 	md4_transform(ctx->hash, ctx->block);
 }
 
@@ -214,7 +214,7 @@ static void md4_final(struct crypto_tfm *tfm, u8 *out)
 	le32_to_cpu_array(mctx->block, (sizeof(mctx->block) -
 	                  sizeof(u64)) / sizeof(u32));
 	md4_transform(mctx->hash, mctx->block);
-	cpu_to_le32_array(mctx->hash, sizeof(mctx->hash) / sizeof(u32));
+	cpu_to_le32_array(mctx->hash, ARRAY_SIZE(mctx->hash));
 	memcpy(out, mctx->hash, sizeof(mctx->hash));
 	memset(mctx, 0, sizeof(*mctx));
 }