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@@ -158,6 +158,30 @@ test_number(void)
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test("0x1234abcd ", "%#-12x", 0x1234abcd);
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test(" 0x1234abcd", "%#12x", 0x1234abcd);
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test("0|001| 12|+123| 1234|-123|-1234", "%d|%03d|%3d|%+d|% d|%+d|% d", 0, 1, 12, 123, 1234, -123, -1234);
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+ test("0|1|1|128|255", "%hhu|%hhu|%hhu|%hhu|%hhu", 0, 1, 257, 128, -1);
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+ test("0|1|1|-128|-1", "%hhd|%hhd|%hhd|%hhd|%hhd", 0, 1, 257, 128, -1);
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+ test("2015122420151225", "%ho%ho%#ho", 1037, 5282, -11627);
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+ /*
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+ * POSIX/C99: »The result of converting zero with an explicit
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+ * precision of zero shall be no characters.« Hence the output
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+ * from the below test should really be "00|0||| ". However,
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+ * the kernel's printf also produces a single 0 in that
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+ * case. This test case simply documents the current
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+ * behaviour.
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+ */
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+ test("00|0|0|0|0", "%.2d|%.1d|%.0d|%.*d|%1.0d", 0, 0, 0, 0, 0, 0);
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+#ifndef __CHAR_UNSIGNED__
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+ {
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+ /*
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+ * Passing a 'char' to a %02x specifier doesn't do
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+ * what was presumably the intention when char is
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+ * signed and the value is negative. One must either &
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+ * with 0xff or cast to u8.
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+ */
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+ char val = -16;
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+ test("0xfffffff0|0xf0|0xf0", "%#02x|%#02x|%#02x", val, val & 0xff, (u8)val);
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+ }
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+#endif
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}
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static void __init
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