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@@ -571,11 +571,10 @@ dependency barrier to make it work correctly. Consider the following bit of
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code:
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q = ACCESS_ONCE(a);
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- if (p) {
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- <data dependency barrier>
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- q = ACCESS_ONCE(b);
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+ if (q) {
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+ <data dependency barrier> /* BUG: No data dependency!!! */
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+ p = ACCESS_ONCE(b);
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}
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- x = *q;
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This will not have the desired effect because there is no actual data
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dependency, but rather a control dependency that the CPU may short-circuit
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@@ -584,11 +583,176 @@ the load from b as having happened before the load from a. In such a
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case what's actually required is:
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q = ACCESS_ONCE(a);
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- if (p) {
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+ if (q) {
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<read barrier>
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- q = ACCESS_ONCE(b);
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+ p = ACCESS_ONCE(b);
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}
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- x = *q;
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+
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+However, stores are not speculated. This means that ordering -is- provided
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+in the following example:
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+
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+ q = ACCESS_ONCE(a);
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+ if (ACCESS_ONCE(q)) {
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+ ACCESS_ONCE(b) = p;
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+ }
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+
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+Please note that ACCESS_ONCE() is not optional! Without the ACCESS_ONCE(),
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+the compiler is within its rights to transform this example:
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+
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+ q = a;
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+ if (q) {
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+ b = p; /* BUG: Compiler can reorder!!! */
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+ do_something();
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+ } else {
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+ b = p; /* BUG: Compiler can reorder!!! */
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+ do_something_else();
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+ }
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+
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+into this, which of course defeats the ordering:
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+
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+ b = p;
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+ q = a;
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+ if (q)
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+ do_something();
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+ else
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+ do_something_else();
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+
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+Worse yet, if the compiler is able to prove (say) that the value of
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+variable 'a' is always non-zero, it would be well within its rights
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+to optimize the original example by eliminating the "if" statement
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+as follows:
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+
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+ q = a;
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+ b = p; /* BUG: Compiler can reorder!!! */
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+ do_something();
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+
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+The solution is again ACCESS_ONCE(), which preserves the ordering between
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+the load from variable 'a' and the store to variable 'b':
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+
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+ q = ACCESS_ONCE(a);
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+ if (q) {
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+ ACCESS_ONCE(b) = p;
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+ do_something();
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+ } else {
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+ ACCESS_ONCE(b) = p;
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+ do_something_else();
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+ }
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+
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+You could also use barrier() to prevent the compiler from moving
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+the stores to variable 'b', but barrier() would not prevent the
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+compiler from proving to itself that a==1 always, so ACCESS_ONCE()
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+is also needed.
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+
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+It is important to note that control dependencies absolutely require a
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+a conditional. For example, the following "optimized" version of
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+the above example breaks ordering:
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+
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+ q = ACCESS_ONCE(a);
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+ ACCESS_ONCE(b) = p; /* BUG: No ordering vs. load from a!!! */
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+ if (q) {
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+ /* ACCESS_ONCE(b) = p; -- moved up, BUG!!! */
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+ do_something();
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+ } else {
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+ /* ACCESS_ONCE(b) = p; -- moved up, BUG!!! */
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+ do_something_else();
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+ }
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+
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+It is of course legal for the prior load to be part of the conditional,
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+for example, as follows:
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+
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+ if (ACCESS_ONCE(a) > 0) {
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+ ACCESS_ONCE(b) = q / 2;
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+ do_something();
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+ } else {
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+ ACCESS_ONCE(b) = q / 3;
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+ do_something_else();
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+ }
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+
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+This will again ensure that the load from variable 'a' is ordered before the
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+stores to variable 'b'.
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+
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+In addition, you need to be careful what you do with the local variable 'q',
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+otherwise the compiler might be able to guess the value and again remove
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+the needed conditional. For example:
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+
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+ q = ACCESS_ONCE(a);
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+ if (q % MAX) {
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+ ACCESS_ONCE(b) = p;
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+ do_something();
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+ } else {
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+ ACCESS_ONCE(b) = p;
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+ do_something_else();
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+ }
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+
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+If MAX is defined to be 1, then the compiler knows that (q % MAX) is
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+equal to zero, in which case the compiler is within its rights to
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+transform the above code into the following:
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+
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+ q = ACCESS_ONCE(a);
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+ ACCESS_ONCE(b) = p;
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+ do_something_else();
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+
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+This transformation loses the ordering between the load from variable 'a'
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+and the store to variable 'b'. If you are relying on this ordering, you
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+should do something like the following:
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+
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+ q = ACCESS_ONCE(a);
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+ BUILD_BUG_ON(MAX <= 1); /* Order load from a with store to b. */
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+ if (q % MAX) {
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+ ACCESS_ONCE(b) = p;
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+ do_something();
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+ } else {
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+ ACCESS_ONCE(b) = p;
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+ do_something_else();
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+ }
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+
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+Finally, control dependencies do -not- provide transitivity. This is
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+demonstrated by two related examples:
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+
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+ CPU 0 CPU 1
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+ ===================== =====================
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+ r1 = ACCESS_ONCE(x); r2 = ACCESS_ONCE(y);
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+ if (r1 >= 0) if (r2 >= 0)
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+ ACCESS_ONCE(y) = 1; ACCESS_ONCE(x) = 1;
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+
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+ assert(!(r1 == 1 && r2 == 1));
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+
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+The above two-CPU example will never trigger the assert(). However,
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+if control dependencies guaranteed transitivity (which they do not),
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+then adding the following two CPUs would guarantee a related assertion:
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+
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+ CPU 2 CPU 3
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+ ===================== =====================
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+ ACCESS_ONCE(x) = 2; ACCESS_ONCE(y) = 2;
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+
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+ assert(!(r1 == 2 && r2 == 2 && x == 1 && y == 1)); /* FAILS!!! */
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+
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+But because control dependencies do -not- provide transitivity, the
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+above assertion can fail after the combined four-CPU example completes.
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+If you need the four-CPU example to provide ordering, you will need
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+smp_mb() between the loads and stores in the CPU 0 and CPU 1 code fragments.
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+
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+In summary:
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+
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+ (*) Control dependencies can order prior loads against later stores.
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+ However, they do -not- guarantee any other sort of ordering:
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+ Not prior loads against later loads, nor prior stores against
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+ later anything. If you need these other forms of ordering,
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+ use smb_rmb(), smp_wmb(), or, in the case of prior stores and
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+ later loads, smp_mb().
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+
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+ (*) Control dependencies require at least one run-time conditional
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+ between the prior load and the subsequent store. If the compiler
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+ is able to optimize the conditional away, it will have also
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+ optimized away the ordering. Careful use of ACCESS_ONCE() can
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+ help to preserve the needed conditional.
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+
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+ (*) Control dependencies require that the compiler avoid reordering the
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+ dependency into nonexistence. Careful use of ACCESS_ONCE() or
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+ barrier() can help to preserve your control dependency.
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+
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+ (*) Control dependencies do -not- provide transitivity. If you
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+ need transitivity, use smp_mb().
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SMP BARRIER PAIRING
|
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@@ -1083,7 +1247,10 @@ compiler from moving the memory accesses either side of it to the other side:
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barrier();
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-This is a general barrier - lesser varieties of compiler barrier do not exist.
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+This is a general barrier -- there are no read-read or write-write variants
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+of barrier(). Howevever, ACCESS_ONCE() can be thought of as a weak form
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+for barrier() that affects only the specific accesses flagged by the
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+ACCESS_ONCE().
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The compiler barrier has no direct effect on the CPU, which may then reorder
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things however it wishes.
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